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About Wharfcreek

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  1. Just to comment on onelife's post above; the plugging in to either jack 1 or 2 does NOT remove the 1 meg shunt from the input circuit. When you're in Jack 1, you have both the 68K input resistors running in parallel, which effectively produces a 34K input resistance level, but the 1 meg grid return resistor is still in the circuit. When you plug into Jack 2 you isolate the 68K resistor on input 1, so you go into the tube grid with just the one 68K input resistor. BUT, the other 68K resistor from input jack 1 is still in the circuit, only now it is in series with the 1 meg grid return res
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