sled

So basically an Open Front Cab?

Is the cab open on both sides?

because 99.99% of people bash them on this forum, including myself... but why do they insist on loading their cabs with them do they make more money this way even though they have the {censored}tiest reputation for speakers... I think you're possibly confusing HCAF with reality.

are you thinking that the 9's literally repeat over time? there are always infinite 9s. remember .333... is equal to 1/3 .999... indicates an infinite number of terms in the series and yes the as the number of terms approaches infinity, .999... converges to 1.0, but this is not the same thing as stating .999... = 1.0

Sigh. You clearly just don't know what you're talking about. The matter is resolved... you are answering a different question of convergence. as terms are added to the series representing .999..., the function converges to 1.0, but that is not the same thing as stating .999... = 1.0 convergence is about finite limits. this is a mathematical requirement, else one could never solve a problem of distance as one object aproaches another because the distance is always halved, but obviously the distance between the two objects does approach Zero. convergence is a rule of necessity and of finite possibilities. that's not the case with .999... in this case, the number .999... will always have an infinitesimal difference with 1.0.

Yes it does. There have already been about 4 or 5 proofs/demonstrations that show this. It seems your flaw of thinking is that with 0.9999.... the 9s end at some point. Well they don't. They keep on going for infinity. If they did end at some point, then yes, you could say "it gets close but does not equal 1." But since they never end, it is equal to 1. Look, no one ever said that it would be easy.... no. .999... approaches 1.0 but never reaches 1.0. there will always be an infinitesimal difference. always.

I don't see the problem. Dreamspace's sum was an infinite sum. 0.999... is an infinitely long decimal. let's make this simple. the OP states .999_ = 1 0.999... does not equal 1.0 no matter how you think about, put it, calculate it it gets close but does not equal 1.0

A) 1/3 = 0.333... B) 3 * 0.333... = 0.999... C) 3 * (1/3) = 1 Ergo, 0.999... = 1 You realize that the repeating notation implies repeating into infinity, right? I can only assume you don't know the difference between a series approximation which I was referring to and 1/3 or pi. regardless, .9999... with a ga-zillion or infinity-1 significant digits does not equal 1.0. it may approximate 1.0, but does not equal 1.0 it may be substituted for 1.0 in calculations, but it still does not equal 1.0

I think what most people here here are missing is the 0.999... part nice try but no, because the series expansion only approaches 1, but never gets there because it would require an infinite number of terms.

my God, HCAF would argue the angstroms width of a nat's ass... :poke: