What Cab To Buy???

[trash maker]

Originally posted by lug cabinet A Ohms X cabinet B ohms divided by cabinet A Ohms + cabinet B ohms example If A is 8 Ohms and B is 4 ohms 8 X 4 divided by 8 + 4 or 32 divided by 12 So an 8 ohm and a 4 ohm box in parallel gives a 2.667 ohm total load.

 

 

 

Now I'm sorted. Thanks Lug, that makes perfect sense!

[BoundandBlocked]

Originally posted by lug cabinet A Ohms X cabinet B ohms divided by cabinet A Ohms + cabinet B ohms example If A is 8 Ohms and B is 4 ohms 8 X 4 divided by 8 + 4 or 32 divided by 12 So an 8 ohm and a 4 ohm box in parallel gives a 2.667 ohm total load.

 

 

 

Just so nobody fries their amp, this formula only works for two impedences.

 

 

FYI

 

 

P.S. Thanks for the tip lug!

[timmerz]

Got 18's in those folded horns, Z-X?

[lug]

Originally posted by BoundandBlocked Just so nobody fries their amp, this formula only works for two impedences.

 

 

32 X32

 

divided by

 

32+32

 

equals 16

----------------------

16 x 16

 

divided by

 

16 + 16

 

equals 8

 

Formula works for any impedence in this or any other solar system.

 

 

edit: I just figured out you meant 2 impedences at a time. To get around this, calculate the first 2 impedences and use the result to calculate against the next impedence, etc.

[timmerz]

Okay, trash maker!
We've pretty much figured out that your 270 will run at pretty much whatever ohms cab or cabs you decide to get, as long as you don't run two 4-ohmers together....
You could do a couple of 8-ohm Avatar cabs, or 1 4-ohm Avatar, or Ampeg cabs or cab, or Ashdowns, etc....
Just make sure you are running a bass cabinet for the best sound.

Now, the all-important question that will give you some decent results:
How much are you willing to spend?

[roners5]

There's been some confusion about calculating total resistance by adding cabs together - it's real simple, when adding resistors in parallel, the formula for the total resistance is:

R total = 1 / (1/R1 + 1/R2 +.... )

Therefore, for two 8 ohm cabs,
R = 1 / (1/8 +1/8) = 1/ (1/4) = 4 ohms.

Similarly, for the 8 ohm and 4 ohm cab,
R = 1 / (1/8 +1/4) = 1/ (3/8) = 8/3, or 2.67

hope this helps:)

[Supafly]

Originally posted by Zeromus-X My entire rig is modular: Ignoring the scoops, it's four small pieces instead of two big ones (big cab and big rack). It meant a lot of trips, but it would fit into any vehicle.

wuts the deal with the scoops? what do they do to ur sound? or are they just stands to put ur rig on top of?

[Zeromus-X]

Originally posted by roners5 There's been some confusion about calculating total resistance by adding cabs together - it's real simple, when adding resistors in parallel, the formula for the total resistance is: R total = 1 / (1/R1 + 1/R2 +.... ) Therefore, for two 8 ohm cabs, R = 1 / (1/8 +1/8) = 1/ (1/4) = 4 ohms. Similarly, for the 8 ohm and 4 ohm cab, R = 1 / (1/8 +1/4) = 1/ (3/8) = 8/3, or 2.67 hope this helps:)

 

 

Why the hell did I not just post that? Hell, I'm a Physics minor. That was a long day.

 

 

wuts the deal with the scoops? what do they do to ur sound? or are they just stands to put ur rig on top of?

 

 

They're 18" subwoofers. Not punchy by any means of the word, but they shake the building no problem. I'm pushing a potential 2000W through the rig, which they happily accept. The Avatars sound great alone, and I only brought those to shows most of the time, but the difference is like adding a subwoofer to your home stereo -- the audience hears the bass with the Avatars, but *feels* it with the scoops too.