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i simplified it a little. f" is still going to be pretty long i think. in case my attachment doesn't work:

 

1)separate f' into the difference of two fractions

2)the first one will reduce to (x-3)^-1/2 or 1/[(x-3)^1/2]

3)the second one will reduce to [(x^2)-3x]/{2[(x-3)^1/2]}

 

so the whole thing will be f'(x)=[(x-3)^-1/2]-[(x^2)-3x]/{2[(x-3)^1/2]}

 

you should be able to get it from there, the second fraction will be a little long.

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