Members justinbass Posted December 5, 2007 Members Share Posted December 5, 2007 Let's say that hypothetically I had a GBE1200 going into a 4 ohm Avatar 410 cabinet. If I wanted to add an Avatar 210 cabinet to the stack, should I add an 8 ohm 210 so that all the speakers are getting sent an equal load? Does it work out that way? Link to comment Share on other sites More sharing options...
Members xOriginalNinjax Posted December 5, 2007 Members Share Posted December 5, 2007 IIRC, no. Even though all the speakers are the same ohm, it wouldn't matter, because the wiring makes them recognized as a different ohm. Basically, it's not the individual speakers, it's the unit as a whole. So, you would want a 4 ohm 210. Link to comment Share on other sites More sharing options...
Members Fiery Furnace Posted December 5, 2007 Members Share Posted December 5, 2007 Right. The 4 ohm would see 67% of the power and the 210 33%. So the 210 would be quieter, the opposite of what you want. Link to comment Share on other sites More sharing options...
Members illidian Posted December 5, 2007 Members Share Posted December 5, 2007 No, you want an 8 ohm 2x10 to go along with a 4 ohm 4x10. (Math review: 1/3 of 6 = 2, 2/3 of 6 = 4) You want to send twice the wattage to the 4x10 as you are to the 2x10, since it has twice the speakers. That means a 4 ohm 4x10 and an 8 ohm 2x10. If you send both cabinets an equal amount (or 50% of the power), then the speakers in the 2x10 are getting twice the wattage as those in the 4x10. Link to comment Share on other sites More sharing options...
Members Crescent Seven Posted December 6, 2007 Members Share Posted December 6, 2007 No, you want an 8 ohm 2x10 to go along with a 4 ohm 4x10.(Math review: 1/3 of 6 = 2, 2/3 of 6 = 4)You want to send twice the wattage to the 4x10 as you are to the 2x10, since it has twice the speakers. That means a 4 ohm 4x10 and an 8 ohm 2x10.If you send both cabinets an equal amount (or 50% of the power), then the speakers in the 2x10 are getting twice the wattage as those in the 4x10. I don't think that's really how it works, though...C7 Link to comment Share on other sites More sharing options...
Members xOriginalNinjax Posted December 6, 2007 Members Share Posted December 6, 2007 I don't think that's really how it works, though...C7 Me neither...someone feel free to correct me, but a cabinet works as a whole, and though you'll not get as much power to the 410...you'll keep equal volume with 2 equal impedance cabs, amirite? Link to comment Share on other sites More sharing options...
Members agedhorse Posted December 6, 2007 Members Share Posted December 6, 2007 No, you want an 8 ohm 2x10 to go along with a 4 ohm 4x10. (Math review: 1/3 of 6 = 2, 2/3 of 6 = 4) You want to send twice the wattage to the 4x10 as you are to the 2x10, since it has twice the speakers. That means a 4 ohm 4x10 and an 8 ohm 2x10. If you send both cabinets an equal amount (or 50% of the power), then the speakers in the 2x10 are getting twice the wattage as those in the 4x10. This is correct, and my suggestion as well. (step to the head of the class and collect your gold star MR. illidian) Link to comment Share on other sites More sharing options...
Members Bluescout Posted December 6, 2007 Members Share Posted December 6, 2007 No, you want an 8 ohm 2x10 to go along with a 4 ohm 4x10.(Math review: 1/3 of 6 = 2, 2/3 of 6 = 4)You want to send twice the wattage to the 4x10 as you are to the 2x10, since it has twice the speakers. That means a 4 ohm 4x10 and an 8 ohm 2x10.If you send both cabinets an equal amount (or 50% of the power), then the speakers in the 2x10 are getting twice the wattage as those in the 4x10. I'll go along with this as well. You'll end up with a 2.6 ohm load with approximately 2/3 of the power going to the 410 and 1/3 to the 210. Link to comment Share on other sites More sharing options...
Members justinbass Posted December 6, 2007 Author Members Share Posted December 6, 2007 This is correct, and my suggestion as well. (step to the head of the class and collect your gold star MR. illidian) Agedhorse to the rescue. Logically, it made sense, but I've learned that very few things in the pro audio world work out the way I think they are supposed to, so I came here knowing someone would be able to shed some light. Thanks! Link to comment Share on other sites More sharing options...
Members agedhorse Posted December 6, 2007 Members Share Posted December 6, 2007 For an application like this, even power sharing between drivers is probably the most important parameter. Say each driver is good for 100 watts, and as suggested each receives 100 watts from the amp at 2.66 ohms, all is "good". (that smiley is for those of you who follow the pro audio fourm) Now say we take the same power amp and choose a 4 ohm 210 cabinet, the power delivered by the amp will be greater due to the 2 ohm load (say roughly 800 rather than 600 watts total) and now it's divided up with 1/2 going to the 210 and the other 1/2 going to the 410. (ohms law) So the 210 will be receiving 400 watts (200 watts per driver) and the 210 will be receiving 400 watts (100 watts per driver) and guess what... 210 is overpowered and is the likely to fail under hard use (or accident/lack of good judgement). The drawback is that the 8 ohm 210 will be about 3dB quieter than the 410, but it also has 3dB less power handling so that's expected. It will contribute to the overall sound and will also improve the low frequency extension a little bit. Hope this helps. Link to comment Share on other sites More sharing options...
Members J. Posted December 6, 2007 Members Share Posted December 6, 2007 Just buy a 610XB2 and be done with it! Link to comment Share on other sites More sharing options...
Members justinbass Posted December 6, 2007 Author Members Share Posted December 6, 2007 Just buy a 610XB2 and be done with it! I drive a civic. I am grateful that my 410 can fit in the backseat. Believe me, I'd LOVE to have a 610xb2. Link to comment Share on other sites More sharing options...
Members agedhorse Posted December 6, 2007 Members Share Posted December 6, 2007 Just buy a 610XB2 and be done with it! Which is pretty much a 4 ohm 410 glued to an 8 ohm 210. Link to comment Share on other sites More sharing options...
Members rpsands Posted December 6, 2007 Members Share Posted December 6, 2007 Get two Neox 212's instead Link to comment Share on other sites More sharing options...
Members agedhorse Posted December 6, 2007 Members Share Posted December 6, 2007 Get two Neox 212's instead Another viable option IMo. Link to comment Share on other sites More sharing options...
Members justinbass Posted December 6, 2007 Author Members Share Posted December 6, 2007 Another viable option IMo. Iin a money-is-no-object world, I'd already own two 212s. Link to comment Share on other sites More sharing options...
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